Solve an algebraic equation involving complex numbers

40 Views Asked by At

Please, solve for $x$ and $y$, $$(x+i)(3-iy)=1+13i, \quad x,y \in \text{Reals}$$

1

There are 1 best solutions below

0
On

$$(x+i)(3-iy) = 1+13i $$

$$ 3x+y+i(3-xy) = 1+13i \implies \left\{ 3x+y = 1 \atop 3-xy = 13 \right.$$

Now solve the system for x and y.