While I was solving a differential equation, I got the following form $$\log(c_1k_1+k_1x^2+2)=2\sqrt{2k_1}y-2\sqrt{2k_1}c_2-2k_1x$$
I want to solve it so as to get $x$ in terms of $y$. Here $c_1,k_1,c_2$ are constants. I thought if I could get a quadratic equation in form of $x$, then I can solve for $x$.