Solve Imaginary Complex Equation

Question

Solve the equation

Question 1:

iz^2+(2−8i)z+4+20i=0

Question 2:

z^4 − 8z^2 + 25 = 0.

Answer 1

Hints: The first one is quadratic equation and the formula for the solution is same whether the coefficients are real or complex. For the second one put $\zeta =z^{2}$ and solve the resulting quadratic equation in $\zeta$. Then take square root.

Answer 2

Using the quadratic Formula we get $$z_1=2-2i$$ or $$z_2=6+4i$$