Solve in positive integers $$a^2-b^2+4a=0$$
I tried considering the residues in mod4 but not so helpful. Any help/hint on how to approach this problem ? Thanks !
2026-04-07 23:45:31.1775605531
Solve in positive integers $a^2-b^2+4a=0$
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HINT : $$\begin{align}\color{red}{a^2}-b^2\color{red}{+4a}=0&\iff \color{red}{(a+2)^2-4}-b^2=0\\&\iff (a+2)^2-b^2=4\\&\iff (a+2-b)(a+2+b)=4\end{align}$$