Solve matrix equation $ CX= B$.

Question

$B=\begin{bmatrix} -1&2&1\\ -2& 2& 3 \end{bmatrix}$

$C=\begin{bmatrix} 2&5\\ 1&2 \end{bmatrix}$

Solve the matrix equation $CX=B$. Can someone show me how to solve this please..

Answer 1

Hint: Assuming that you know how to solve a system of the form $A\cdot x = b$, where $A$ is a square matrix and $x,b$ are column vectors, then it is sufficient to solve the $3$ systems: $$C\cdot x_1 = \begin{bmatrix} -1 \\-2 \end{bmatrix}\\[2ex] C\cdot x_2 = \begin{bmatrix} 2 \\2 \end{bmatrix}\\[2ex] C\cdot x_3 = \begin{bmatrix} 1 \\3 \end{bmatrix} $$ The solution $\mathbf{x}$, which is a $2\times 3$ matrix will be the horizontal concatenation of the $2\times 1$ column vectors $x_1,x_2,x_3$, i.e. $\mathbf{x} = \begin{bmatrix} x_1 & x_2 & x_3\end{bmatrix}.$

You may check that $C\cdot \mathbf{x} = B$.

Answer 2

As C is non singular ($|C|=-1$) you can do the following:

$$CX=B \implies X =C^{-1}B$$