Use iteration method to solve:
$1.$ $T(n) = T(n-1) + \frac{1}{n},\,(T(0)=1)$
$ 2.$ $T(n) = 3T\left(\dfrac{n}{3}\right) +1,\,(T(3)=1)$
Use iteration method to solve:
$1.$ $T(n) = T(n-1) + \frac{1}{n},\,(T(0)=1)$
$ 2.$ $T(n) = 3T\left(\dfrac{n}{3}\right) +1,\,(T(3)=1)$
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I'll do the first one for you. Just note that,
$$ T(n) = T(n-1) + \frac{1}{n}=T(n-2) + \frac{1}{n-1}+\frac{1}{n}$$
$$= T(n-3) + \frac{1}{n-2}+\frac{1}{n-1}+\frac{1}{n}$$
$$ = T(n-4) + \frac{1}{n-3}+\frac{1}{n-2}+\frac{1}{n-1}+\frac{1}{n} $$
$$ \implies T(n)=T(0)+\sum_{i=1}^{n}\frac{1}{i}=1+H_n, $$
where $H_n$ are the harmonic numbers.