I have difficulties with these type of problems:
Solve the comparison: $\displaystyle67x + 17 \equiv 0\pmod{28}.$
I'm sure it is something very simple but I'm stuck on it more than $2$ hours :( .
Any help would be greatly appreciated.
2026-03-29 16:01:23.1774800083
Solve the comparison
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As $67\equiv11\pmod{28}$
$$67x+17\equiv0\pmod{28}\iff 11x+17\equiv0\iff11x\equiv-17\equiv11\pmod{28}$$
$$\iff x\equiv1\pmod{28}$$
Using property $\#12$ of this and as $(11,28)=1$