The diophantine equation that needs to be solved is $kx^2-y^2=3$ with the added conditions that:
\begin{cases}k>1\\k\text{ not a square}\\ x>2\\ x\equiv 0\mod 2\\ x/2 \not| \ k \\ x/2 \text{ is prime}\\y\ge 2a_0-1\ \text{for a given $a_0>1$ (If the general case is difficult, you can take $y\ge 3$)}\\ y\equiv 1\mod 2 \end{cases}
Does there exist solutions to this?
Is there a possibility of finding a parametrization of the solution space, given that there exists solutions?
Some first solutions
(k,x,y):gp-code: