Solving Area problem using integral, without drawing the graph

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Example problem:

Calculate the total area bounded by $f(x)=\ln(x)$, $g(x)=2\ln(x)$, $x=1, x=e.$

Solution:

This can be done without sketching the case. $g(x) \ge f(x) \ge 0$ in $[1,e]$, and the area $A$ is $$ \int_{1}^{e} 2\ln(x)-\ln(x) dx = \int_{1}^{e} \ln(x) dx = 1$$


Question: Is there a general techique for this kind of problem, such that does not require sketching? (Because what if the function is complicated to be drawn)

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Consider we want to write the somputation formally, we will come up with: $$A = \int_{\{x\in[1,e]: f(x) > g(x)\}}f(x)-g(x)\mathrm{d}x + \int_{\{x\in[1,e]: g(x) > f(x)\}}g(x)-f(x)\mathrm{d}x = \\ = \int_1^e|f(x)-g(x)|\mathrm{d}x = \\ = \int_1^e \max\{f(x),g(x)\}-\min\{f(x),g(x)\}\mathrm{d}x $$

In some cases it might be simple to calculate the cases (e.g. for continous functions we can find the zeros of $f-g$ and see how the function behaves between them), but sometimes it might get somplicated.