Solving cycles - Permutation group

38 Views Asked by At

I’m trying to get $(16523)$ using $(132)$ and $(13456)$ but I’m not able to. Can someone help?

1

There are 1 best solutions below

1
On

Check Here

$$(1 6 5 2 3) = (1 3 4 5 6)^3(1 3 2)(1 3 4 5 6)$$