$$(2^{x}-1)(2^{x}+4)(2^{x}-6)=0$$
My thinking: At least one of the three terms given above should be equal to $0$.
But the middle term will never be equal to zero because $2^{x}$ can not be equal to a negative number.
Therefore $2^{x} -1=0$ thus $x=0$ and/or $2^{x}-6=0$ thus use log to solve for $x$.
Is my thinking correct?