Solving for an exponential variable that can not be issolated through factorisation.

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$$(2^{x}-1)(2^{x}+4)(2^{x}-6)=0$$

My thinking: At least one of the three terms given above should be equal to $0$.

But the middle term will never be equal to zero because $2^{x}$ can not be equal to a negative number.
Therefore $2^{x} -1=0$ thus $x=0$ and/or $2^{x}-6=0$ thus use log to solve for $x$.

Is my thinking correct?