I have an equation where
$$ \frac{(c^n + y)}{(a^n - b^n)} = \frac{C}{(a-b)} $$
In my case, $ y << c^n $ , so I could potentially simplify the equation to:
$$ \frac{c^n}{(a^n - b^n)} = \frac{C}{(a-b)} $$
or further
$$ \left(\frac{a}{c}\right)^n - \left(\frac{b}{c}\right)^n = \frac{(a-b)}{C} $$
I have everything except $n$.
Can I solve for $n$, given $a$, $b$, $c$ and $C$?
Can I solve for $n$, given $a$, $b$, $c$, $y$ and $C$ without having to resort to the approximation and taking away $y$?