Solving for $x$, ${\sqrt{7x-5}} - {\sqrt{2x}} = {\sqrt{15 - 7x}}$

Question

could I please have some help solving this equation for $x$ ?

${\sqrt{7x-5}} - {\sqrt{2x}} = {\sqrt{15 - 7x}}$

Thank you

Answer 1

$${\sqrt{7x-5}} - {\sqrt{2x}} = {\sqrt{15 - 7x}}$$ $$7x-5 - 2{\sqrt{2x(7x-5)}}+2x =15 - 7x$$ $$16x-20 =2{\sqrt{2x(7x-5)}}$$ $$8x-10 ={\sqrt{2x(7x-5)}}$$ $$64x^2-160x+100=14x^2-10x$$ $$50x^2-150x+100=0$$ $$x^2-3x+2=0$$ $$x=1,x=2$$ only $x=2$ is solution