I was trying to solve for $y$ in this equation: $4+x^3+y^3-3xy = 0$. I put it into WolframAlpha and it gave me an complicated answer. It appears like it used the cubic formula, except when I tried to view the steps on Wolfram, it showed this strange substitution: 
So my question is how would you finish solving this, or is there another simpler way that doesn't involve creating a new variable like $λ$?