Solving $\frac{\partial u}{\partial t}+(x^2+1)\frac{\partial u}{\partial x}=0$ with initial condition $u(x,0)=f(x),x\in\mathbb R.$

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Solve $\frac{\partial u}{\partial t}+(x^2+1)\frac{\partial u}{\partial x}=0$ with initial condition $u(x,0)=f(x),x\in\mathbb R.$

Under which conditions does the solution exists?

Is it unique?

What I've done:

The general solution is $u(x,t)=\phi(t-\arctan(x))$.

Applying the initial condition we have $u(x,t)=f(\tan(t-\arctan(x)))$.

Thus the solution exists when $(t-\arctan(x)) \in I,$ where $I=\big(\frac{-(k+1)\pi}{2},\frac{(k+1)\pi}{2}\big),k\in\mathbb N.$


Am I correct in the solution ?

How do I check uniqueness?