Given $z_1,z_2$ are complex numbers such that sum of their squares is a real number and $$z_1(z_1^2-3z_2^2)=2$$ and $$z_2(3z_1^2-z_2^2)=11.$$ I need to find the value of sum of squares of two complex numbers.
My intuition helped me guess the answer $z_1=2$ and $z_2=1$ but I couldn't prove it.