I am given to solve the Cauchy problem :
$$ \frac{dy}{dx}=(x-y)^2 $$ given $y(0)=0$.
I am not able to arrive at any standard solvable form of ODE.
2026-03-25 14:22:51.1774448571
solving the ODE $\frac{dy}{dx}=(x-y)^2$ given $y(0)=0$
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Hint: Substitute $$x-y=u$$ then we get $$y'=1-u'=u^2$$ Can you finish?