Solving $x^3-(2+2n)x^2-(4n+1)x+(2m^2-2n)=0$ for real $m$ and $n$

67 Views Asked by At

I do not know how to solve this cubic equation. The background of this problem is from lagrange multiplier. I use lagrange multuplier to find the distance from point(m,n) to parabola. and I stuck with this step.

$$ x^3 - (2+2n)x^2 - (4n+1)x + (2m^2 - 2n) = 0 $$ when $m$ and $n$ are real numbers.

How to solve it?

Thank you.