How does one solve the congruence $$x^{3}+x^{2}+1 \equiv 0\pmod{27}$$ First reducing the congurence $\pmod{3}$ i get $x=1$ as one solution. But not sure how to go from here.
2026-03-31 14:24:55.1774967095
Solving $x^{3}+x^{2}+1 \equiv 0\pmod{27}$
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