I'm already long time from school. I want to solve y from this equation:
$x = 10^\frac{(y - 109)}{32}$
How can I do that?
In real life y is the rain intensity, and x is number of millimeters rain per hour.
I'm already long time from school. I want to solve y from this equation:
$x = 10^\frac{(y - 109)}{32}$
How can I do that?
In real life y is the rain intensity, and x is number of millimeters rain per hour.
$$\frac{y-109}{32}=\log_{10}x$$ or $$y=32\log_{10}x+109.$$