Sue and Tim play the following game. They throw a fair die alternately, starting with sue and the winner is first to obtain a 6.
Find the probability that Sue wins with her second throw
The answer in the mark scheme is 5/6 x 5/6 x 1/6 and Im not sure how they got this Any help would be greatful
The probability that the first throw of Sue is not a $6$ is $\frac56$. Then the probability that the first throw of Tim is not a $6$ is again $\frac56$.
And then the probability that for the second throw of Sue she gets a $6$ is $\frac16$.
So the total probability that all these things happen in a row is $\frac56\cdot\frac56\cdot\frac16$.