Suppose $g(x) = 1$ if $x=0$ and $g(x)=0$ otherwise, would that be a considered a step function? I assume it is because $g(x)$ can be written as the indicator function acting on $x=1$? Sorry if this question sounds silly.
2026-02-23 05:57:28.1771826248
Step Function confusion
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Yes, because a step function is a function that can be written as finite linear combination of indicator functions.