What are the steps to simplify the first fraction to the second?
$$\frac{\frac{3-(3+h)}{3(3 + h)}} {h} \implies \frac{-1}{3(3 + h)}$$
I assume the first step would be to re-write it like so:
$$\frac{3-(3+h)}{3(3 + h)h}$$
But after that I don't know where to go...
Notice, the following steps $$\frac{3-(3+h)}{3(3+h)h}$$$$=\frac{3-3-h}{3(3+h)h}$$$$=\frac{-h}{3(3+h)h}$$Cancelling $h$ in numerator & denominator $$=\frac{-1}{3(3+h)}$$