$f$ is continuous and $$ \int_{a}^{b} x^nf(x) dx=0 $$ for every $n\leqslant N$.
Prove that $f$ has at least $N+1$ zero points at $(a,b)$.
$f$ is continuous and $$ \int_{a}^{b} x^nf(x) dx=0 $$ for every $n\leqslant N$.
Prove that $f$ has at least $N+1$ zero points at $(a,b)$.
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Hint: If $f$ has $N$ or fewer zero-points on $(a,b)$, then there exists a non-zero polynoimal $p(x)$ of degree $N$ such that $f(x)p(x) \geq 0$ for all $x \in [a,b]$.