Strong operator and ultrastrong topologies are the same on bounded subsets

33 Views Asked by At

In class, we proved that weak operator and ultraweak topologies coincide on norm-bounded subsets of $\mathcal{B} (\mathcal{H})$ (here, $\mathcal{H}$ is a Hilbert space) using Banach-Alaoglu. This had me wondering whether the same is also true for strong operator and ultrastrong topologies. Wikipedia claims it is, but doesn't give a reference. Does there exist an elementary proof of this?