Struggling to reach answer with algebraic fractions

Question

The question is $$\frac{2x^3-x^{-3}}{x^3}$$

and the answer is $$2-x^{-6}$$

I have been trying but cannot get to the correct answer using the methods I know. If anyone can explain to me how to do it I would be extremely grateful.

Answer 1

Hope this is clear now: $$\frac{2x^3-x^{-3}}{x^3} = \frac{2x^3}{x^3} -\frac{x^{-3}}{x^3} = 2 - \frac 1 {x^3}\cdot\frac 1 {x^3} =2 - \frac 1 {x^6}= 2-x^{-6} $$