Subgroups of Quotient Groups

Question

Quick Question:

If $H \unlhd G$, then I know that the subgroups of $G/H$ are of the form $K/H$ where $K$ is a subgroup of $G$ containing $H$.

If you have a subgroup $A$ of $G$ and $A$ does not contain $N$, is the convention that $A/N$ is the trivial group or is this group not even defined (I would imagine the latter, but just want to make sure as I have not seen this anywhere)?

Answer 1

Then $A/N$ is not even defined.