I am Curious if the following is mathematically correct:
Let $a$ be the infinite set of all nonnegative integers $0,1,2,3...$.
I take from $a$ some of its elements, say integers $10$, $11$, and $12$ only.
So now we have a new set $a'$ that is the infinite set of all nonnegative integers $0,1,2,3...$ except for $10$, $11$, and $12$.
If I subtract: $a-a'$ the result is a set comprised of $10$, $11$, $12$ only. Is this correct? Can one subtract infinities like this?
If yes, does this mean that $a \gt a'$(despite that both are infinite)?
The set of positive integers is denoted $\mathbb{Z}^+=\{1,2,3,\dots\}$ and has cardinality $\aleph_0$. The set of positive integers excluding $10,11,12$ also has cardinality $\aleph_0$. The difference between the sets is indeed $\{10,11,12\}$ and its cardinality is $3$. To answer your question, you should read more about cardinal number arithmetic.