Let $\alpha$ be the only real root of $p(x)=x^3-3x^2+5x-17$ and $\beta$ the only real root of $q(x)=x^3-3x^2+5x+11$. Compute $\alpha + \beta$.
I've noticed that the two graphs are just the same shifted vertically (the first coefficients are equal except for the last), but I don't know if it is useful.
(This is supposed to be doable without any calculator)
Re-arrange $p(x)$ and $q(x)$:
\begin{align*} p(x) &= x^3-3x^2+5x-17 \\ &= (x-1)^3+2(x-1)-14 \\ q(x) &= x^3-3x^2+5x+11 \\ &= (x-1)^3+2(x-1)+14 \end{align*}
If $p(1+x)=-q(1-x)=0$, then $$ \left \{ \begin{align*} 1+x &= \alpha \\ 1-x &= \beta \end{align*} \right.$$
$$\fbox{$\alpha+\beta=2$}$$