Sum of two norms is a norm

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I have to prove, that a sum of two norms, is a norm: $$\|\cdot\| := \|\cdot\|_a + \|\cdot\|_b.$$

Properties to satisfy:

$ (a)~ \|x\|=0 \iff x=0 $

$ (b)~ \|\alpha x\|=|\alpha| \|x\| $

$ (c)~ \|x+y\| \le \|x\|+\|y\| $

I'm not sure how to show all of these properties. I mean, it sounds logical and I know it's true, but I have a blank space in my mind.

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Remember to prove this you need to assume that $\|\cdot\|_{a}$ and $\|\cdot\|_{b}$ are both norms, and thus satisfy the definition. Thus implies what you need to prove.

One puts in an abstract vector $x$, and show the equality of the statements.

For example: For the first part of the definition, if $\|x\|= \|x\|_{a} + \|x\|_{b} = 0$, what can you say about $\|x\|_{a}$ and $\|x\|_{b}$ (based on the fact that $\|\cdot\|_{a}$ and $\|\cdot\|_{b}$ both satisfy this part of the definition)?