Suppose that the $n$ Gersgorin discs of $A \in M_n$ are mutually disjoint. If $A$ is real, show that every eigenvalue of $A$ is real.

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Suppose that the $n$ Gersgorin discs of $A \in M_n$ are mutually disjoint. (a) If $A$ is real, show that every eigenvalue of $A$ is real. (b) If $A \in M_n$ has real main diagonal entries and its characteristic polynomial has only real coefficients, show that every eigenvalue of $A$ is real.

The fact I tried to use is that if the union of $k$ of the $n$ discs that comprise $G(A)$, the union of Gersgorin discs, forms a set $G_k(A)$ that is disjoint from the remaining $n-k$ discs, then $G_k(A)$ contains exactly $k$ eigenvalues of $A$. However, I don't think this fact leads to the result I'm trying to show. I'm not sure how to approach this problem. Any solutions, hints, or suggestions would be appreciated.

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The proof of both statements is the same. If the characteristic polynomial has all real coefficients, then any complex root $\lambda$ is accompanied by its conjugate $\overline{\lambda}$. But if a disk is centered on the real axis, then it contains $\lambda$ if and only if it contains $\overline{\lambda}$. Derive a contradiction of the second part of Gerschgorin's theorem from this fact.