Suppose the quadratic covariation of process $X$ with $B$ is constant - then is $X$ linear in $B$?

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Suppose $X$ is progressively measurable with respect to the filtration of a Brownian motion $B$ and $L^2$. Suppose that $[X,B](T)=C$ for some real constant $C$, then is it true that $X$ is linear in $B$?

Because $X$ is $L^2$ we can use the martingale representation theorem to get that $$X(t)=f(t)+\int_0^t\phi(s) dB(s),$$

for some progressively measurable $\phi$.

Therefore the quadratic covariation is

$$\int_0^T \phi(s) ds=C.$$

If this is constant (independent of $B$), then is it true that $\phi(s)$ is independent of $B$? If not, what can we assume on $X$?