Determine infimum, supremum, maximum, minimum of the following
$(-2,2] \cup (3,8]$ I would say the infimum is -2, no minimum, supremum=maximum=8 ?
$(\mathbb{R}$ \ $\mathbb{Q}) \cap [–5,5]$ So the intersection is the empty set, so there are no suprema/infimum?
$\bigcup_{n \in \mathbb{N}} (1+1/2^n, n+2)$ wouldn't the union be $(1, \infty)$? So supremum would be infinity and infimum would be 1 and no minimum and maximum?
$\bigcap_{n=1}^{\infty} (1-1/n^2, 2-1/n) $ would the intersection be 1? Then what could I say about supremum and infimum?
Edited the typo in 2)