Surface integral of complex function using residues

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I am stuck with a math problem that I thought should be straightforward. Maybe I'm missing something here and you can help me.

The key idea is that I have to integrate this function over a volume:

$ I = \int_V \frac{\partial u}{\partial x} dV $

where the volume V is in the x-y plane. I thought of using complex analysis since I do not have a closed form for u, but instead I have an expression for F(z) with

$ F(z) = u + iv \quad \text{with} \quad z=x+iy$

I therefore thought of using complex analysis.

I'll explain my first approach, which I believe was incorrect: First, I thought of the integral "I" as the real part of the whole thing:

$ I = Re\left(\int_V \frac{d F}{d z} dV \right)$

and then use the divergence theorem to cast this not as a volume integral, but as a contour integral.

As you can see already, the approach is wrong in many levels: mostly because dF/dz does not correspond to the divergence (does it?).

I am sure there should be an easy way of converting this integral into a contour integral, but I have been unsuccessful finding it.

Anyone has dealt with this type of problem before?

Many thanks in advance!

Ignacio

Edit:

Ok, after some research I found out that, by defining J as

$J = \displaystyle \frac{i}{2} \int_V \frac{dF}{dz} dz \wedge dz^* $

it is shown that I = Re(J), since $dz\wedge dz^* = -2idxdy$

I believe that J can be calculated using Stokes theorem... work in progress...