synthetic division with $i$ in divisor

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I divided $x^3-4x^2+4x-16$ by $-2i$ using synthetic division and got a remainder of $-8i-8$. Is that right? I'm not sure I'm doing this right.

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Hint: Let $$p(x)=x^3-4x^2+4x-16$$ Evaluate $p(\alpha)$ that will be reminder when $p(x)$ is divided by $x-\alpha$

But we have $$p(x)=x^3-4x^2+4x-16=(x-4)(x^2+4)=(x-4)(x+2i)(x-2i)$$ what can you conclude from this?

See Factor theorem and Polynomial remainder theorem