System of equations $\lfloor x\rfloor+\{y\}=1.2,\ \{x\}+\lfloor y\rfloor = 3.3$

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Solve over reals the system of equations:

$$\lfloor x\rfloor+\{y\}=1.2$$

$$\{x\}+\lfloor y\rfloor = 3.3$$

My idea: Because $0\le \{y\} < 1$ and $\lfloor x\rfloor$ is an integer, the only possibility is $\lfloor x\rfloor = 1$ and $\{y\}=0.2$.

Because $0\le \{x\} < 1$ and $\lfloor y\rfloor$ is an integer, the only possibility is $\lfloor y\rfloor = 3$ and $\{x\}=0.3$.

The solution is $x=\lfloor x\rfloor+\{x\}=1.3$ and $y=\lfloor y\rfloor+\{y\}=3.2$. Is it correct? Can I write this idea this more cleanly?

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That's right. You can make it cleaner by taking the integer and fractional parts, and using the fact these functions are idempotent (in fact, they're linear projection operators summing to the identity).