Given the following systems of modular equations:
$$ 4^{x}+x^{2}\equiv 1 (mod \: 6)$$
$$7x\equiv 3 (mod \: 9)$$
$$15x\equiv 10 (mod \: 25)$$
Which x solves the system ?
It is possible to make use of Chinese remainder theorem, but what to do with Equation 1 ?
Thanks
Hint: The (positive) powers of $4$ are all congruent to $4$ mod $6$, so that first equation simplifies to
$$x^2\equiv3\mod6$$
Can you take it from there?