By the Strum theory it is easy to see that the equation $\tan(\alpha)=\alpha$ has not complex roots and it's real roots occur at zero and near $(2n+1)\pi/2,\ n\in Z^{+}$. I am interesting to know that is there any other way to see that the above equation has not complex roots?
2026-05-04 18:05:01.1777917901
$\tan(\alpha)=\alpha$ has not complex roots?
93 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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