I am doing the calculus course on edX and I stumbled across this explanation for a problem (I am not asking for the answer, just elaboration on a specific part).
$$x = 100$$
$$g(x) = \sqrt{x} = 10$$
But how is it that $g'(x) = 0.05$?
I thought that the formula was $g'(x) = 1/2* x^{-1/2}$: But when I plugged $x = 100$, I didn't get $0.05$ as the result.
You should get $0.05$ as the result of $g'(100)$:
$$\dfrac12(100^{-1/2})=\dfrac12\times\dfrac1{100^{1/2}}=\dfrac12\times\dfrac1{10}=0.05$$