Tangent line to $f(x)=\ln(x) -x + 2$ at $(3, \ln(3)-1)$ intersecting $x$ axis

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What is the $x$-value at which the tangent line to $f(x) = \ln(x) -x + 2$ at $(3, \ln(3)-1)$ intersects the $x$-axis?

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Here are the steps you should follow:

  1. Differentiate $f(x)$ to get $f'(x)$

  2. Plug in the $x$ value in $f'(x)$

  3. Get the equation of the line in the form $y = mx+b$ and determine $b$

  4. Once you have the equation of the line substitute $y = 0$ and isolate for $x$