Taylor expansion of a function of two variables, one of which is an exponent

37 Views Asked by At

Which is the Taylor series of the second order, centered at the origin, of the function:

$$ f(x,y)=(1+x^3)^y $$

1

There are 1 best solutions below

0
On BEST ANSWER

You might write your function as $ f(x,y) = \exp(y \log(1+x^3))$. Now $\log(1+x^3) = O(x^3)$, so $$f(x,y) = \exp(O(x^3 y)) = 1 + O(x^3 y)$$ Thus the Taylor expansion to second order is just $1$.