Using the prime number theorem, show that:
$\vartheta (x) \sim x$
Where $\vartheta (x) := \sum_{p \le x} \log p$
Any help on this would be great, thanks in advance.
Using the prime number theorem, show that:
$\vartheta (x) \sim x$
Where $\vartheta (x) := \sum_{p \le x} \log p$
Any help on this would be great, thanks in advance.
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Just notice that $$\vartheta (x)=\int_1^x \ln t\ \text{d}\pi(t)=\pi(x)\ln x-\int_1^x\dfrac{\pi(t)}{t}\ \text{d}t$$ Applying Prime number theorem $$\pi(x)\sim \dfrac{x}{\ln x}$$ Q.E.D.