This theorem states that "Any group is isomorphic to a subgroup of a group permutations." I only ask if someone could provide a simple example so that i can fully understand this theorem.
2026-03-27 10:44:27.1774608267
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The Cayley Representation Theorem.
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For example, say you have a finite Abelian group which is a product of cyclic groups of orders $q_1,q_2,\ldots,q_n$. Then let $N = \sum_j q_j$ and consider the permutation group $S_N$. For each $q_j$, choose a subset of $\{1,2,\ldots,N\}$ of size $q_j$ where all the subsets are disjoint. Then consider the subgroup generated by a set of cycles, where you have one cycle over each disjoint subset of characters that you picked. The subgroup generated by these cycles will be isomorphic to your Abelian group.
You ask for a simple example, so here is one: Consider the group $\mathbb{Z} / n\mathbb{Z}$. This is a finite abelien group under addition of order $n$.
Let $$ \phi: \mathbb{Z} / n\mathbb{Z} \longrightarrow S_n $$ given by $$ \phi([1]) = (1\; 2\; 3\; \dots \; n ). $$ So $$ \phi([m]) = (1\; 2\; 3\; \dots \; n )^m. $$ Then $\phi$ is a injective. Note that $S_n$ is a multiplicative group.
Note that all you had to do here was to find an element of order $n$ in $S_n$. In fact, the above example is easily extended to embedding any cyclic group in some permutation group (since any cyclic group is isomorphic to a $\mathbb{Z} / n\mathbb{Z}$ for some $n$).