The diophantine $a^{11} + b^{11} = c^{11} + d^{11} = s$ for Eisenstein integers.

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Let $a,b,c,d,s$ be distinct nonzero Eisenstein integers.

Claim : $$a^{11} + b^{11} = c^{11} + d^{11} = s$$

has only a finite number of solutions for any given $s$.

In fact at most $22$ for any $s$.

Is this true ? Is it known or studied ?

Any references ?

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The equation,

$$a^{11}+b^{11} = c^{11}+d^{11}\tag1$$

is difficult to solve using quadratic integers, especially if we limit ourselves to Eisenstein integers. So we generalize things slightly and consider the ring of quadratic integers of $\mathbb{Q}(\sqrt{D})$ that is both a "principal ideal domain" and "Euclidean domain". Then for negative discriminants $D$ we only have five:

$$D = (-1,\,-2,\,-3,\,-7,\,-11)$$

and, voila, we have the single known identity for $11$th powers,

$$\left(\frac{1+\sqrt{-7}}2\right)^{11}+\left(\frac{1-\sqrt{-7}}2\right)^{11}=\left(\frac{1+\sqrt{-11}}2\right)^{11}+\left(\frac{1-\sqrt{-11}}2\right)^{11}= 67$$

given in this 2017 post. I don't know of any other solution for $(1)$ using quadratic integers, nor if,

$$a^{13}+b^{13} = c^{13}+d^{13}\tag2$$

is also solvable, but is probably not.