Given a finite rank (bounded) operator $F:H\to H $ when H is a separable Hilbert space, is it true that the image of the closed unit is compact? I know it is pre-compact, so the question is whether it's closed.
2026-03-25 06:12:50.1774419170
The Image of the Closed Unit Ball Under Finite Rank Operators
185 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in HILBERT-SPACES
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