The ‎inclusion relation $\sigma(ab) ‎\subseteq ‎\sigma(a)‎\sigma(b)$ is not true for all Banach algebras

322 Views Asked by At

Let ‎‎$‎A$ ‎be a‎ ‎unital ‎abelian‎ ‎Banach ‎algebra. ‎Give ‎me ‎an ‎example ‎that two ‎following ‎inclusion ‎relations ‎is ‎not ‎true ‎for ‎all ‎Banach ‎algebras‎

$$\sigma(a+b) ‎\subseteq ‎\sigma(a)+‎\sigma(b) ‎‎‎‎‎‎\forall a,b ‎\in A‎‎‎‎$$ ‎‎‎‎

$$\sigma(ab) ‎\subseteq ‎\sigma(a)‎\sigma(b) ‎‎‎‎‎‎\forall a,b ‎\in A‎‎‎‎$$

1

There are 1 best solutions below

5
On BEST ANSWER

Actually, these inclusions do always hold for elements $a$ and $b$ of a unital commutative Banach algebra. (If you take away commutativity, you can find counterexamples with 2-by-2 matrices.)

You can see this by applying the Gelfand transform $\Gamma:A\to C(X)$, with $X$ the maximal ideal space of $A$, because for all $a\in A$, $\sigma(a)=\Gamma(a)(X)$. The inclusions $(f+g)(X)\subseteq f(X)+g(X)$ and $(fg)(X)\subseteq f(X)g(X)$ are clear for arbitrary functions $f,g:X\to\mathbb C$.