If I have
$$F(x)= \frac{1}{1+e^{-x}}$$ where $x \in \mathbb{R}$
How may I find the PDF?
2026-04-20 09:51:54.1776678714
The logistic distribution PDF
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By the chain rule, differentiating gives $\frac{e^{-x}}{(1+e^{-x})^2}$, which is notably an even function. It's often worth noting $F^\prime=F(1-F)$.