The property of closed subspace

242 Views Asked by At

We know that a set is closed if and only if every convergent sequence with elements in the set has a limit point in the set.

I am reading a paper, and the paper claims that the following is due to S is a closed subspace:

Suppose we know:

S is a closed constraints subspace. K is a matrix.

  1. $K \in S$
  2. $K(GK)^n \in S, \forall n$

then

$\sum_{n=0}^\infty K(GK)^n \in S$
(Note: $\sum_{n=0}^\infty K(GK)^n$ is a convergent summation and $(GK)^n$ is convergent sequence)

Why is this related to the condition that $S$ is a closed subspace?
(This is the sum of this sequence.)

Paper title: A Characterization of Convex Problem in Decentralized Control

1

There are 1 best solutions below

2
On BEST ANSWER

I suppose you are talking about some linear space. In this case, we know that the partial sums $$P_m := \sum_{n=0}^{m} K(GK)^n$$ are in $S$, because they are just finite sums of elements in $S$. If the limit $P = \lim_{m \to \infty} P_m$ exists, we know that $P \in S$ since $S$ is closed.

However, I believe that there is some kind of convergence argument missing that tells you that $P_m$ is a convergent sequence.