The sum of the present ages of a mother and her son is $42$. When the mother was same age as her son now, her son wouldn't be born until $15$ years later. What was the mother's age when her son was born?
This question had seemed a bit complex. However, we can say that
$$M + S = 42 \tag {1}$$
where $M = \text{Mother}$, $S = \text{Son}$
Mother's age $15$ years ago before her son was born
$$ M-t = -S-15 \tag{2}$$
$$t = \text{passed time}$$
This is where I'm stuck. I'll be waiting for your professional helps.
We have $M+S=42$, assume that the mother is $t$ years older than her son.
Currently, the mother is $M$ years old and the son is $S$ years old.
$\Rightarrow$ $t$ years ago, the mother was $M-t=S$ years old and her son was $S-t$ years old. Note that the son wouldn't be given birth until $15$ years later, so at this point we consider that her son was $-15$ years old or $S-t=-15$.
We have this set of equations:
$${\begin{cases}M+S=42\\M-S-t=0\\S-t=-15\end{cases}}$$
After solving this, you can check the answer below.