The volume of the solid obtained by rotating the region bounded by $y=5x$ and $y=x^2$ about$ x=5$.

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How do I solve this? I tried to give the integral from $0$ to $25\pi((5x)^2-(x^2)^2)$ but it is wrong and I don't understand why I also need it with cylindrical shells.

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Solve the integral $$\pi\int^{25}_0\left[\left(5-\frac{y}{5}\right)^2-\left(5-\sqrt{y}\right)^2\right]dy$$ graph